beta

Feb 9 2008, 09:50 PM

actually, you can use either. of course, if you use #111111, it will show up as #111111 in the dropdown - as well as in the UBBC that's placed in the textarea.

here's a different version that lets you have a different text than the value.

Code:

 

<script type="text/javascript"> <!--
var colors = [["Displayed in Dropdown", "Displayed in UBBC"], ["Ditto", "Ditto 2"]];
if(document.posting && document.posting.fcolor) $("select[@name=fcolor]").each(function() {
for(var j = 0, f = this.options.length; j < colors.length; j++) this.options[f + j] = new Option(colors[j][0], colors[j][1]);
for(var i = 1; i < this.options.length; i ++) this.options[i].style.color = this.options[i].value;
});
// --> </script>

so, if i had it like this: ["Red", "#123456"];
the dropdown list would say Red, but the tag would be [ color=#123456 ] - get it?

Code:

 

<script type="text/javascript"> <!--
var x = [["Deeppink2", "#ee1289"], ["Slateblue", "#7a67ee"], ["Royalblue", "#3333ff"], ["Turquoise2", "#00e5ee"], ["Seagreen2", "#4eee94"], ["Red3", "#cd0000"], ["Magenta3", "#cd00cd"], ["Papaya", "#ffff7e"], ["Plum2", "#eaadea"], ["Violetred", "#db2645"]];
if(document.posting && document.posting.fcolor) (function() { var z = document.posting.fcolor;
for(var i = 0, j = z.options.length; i < x.length; i ++) z.options[i + j] = new Option(x[i][0], x[i][1]);
for(var i = 1; i < z.options.length; i ++) z.options[i].style.color = z.options[i].value; })();
// --> </script>

Code:

 

for(var i = 1; i < z.options.length; i ++) z.options[i].style.color = z.options[i].value;